Y=-2x^2+15.19

Solution for Y=-2x^2+15.19 equation:

=-2Y^2+15.19

We move all terms to the left:

-(-2Y^2+15.19)=0

We get rid of parentheses

2Y^2-15.19=0

a = 2; b = 0; c = -15.19;
Δ = b2-4ac
Δ = 02-4·2·(-15.19)
Δ = 121.52
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{121.52}}{2*2}=\frac{0-\sqrt{121.52}}{4}
=-\frac{\sqrt{}}{4}
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{121.52}}{2*2}=\frac{0+\sqrt{121.52}}{4}
=\frac{\sqrt{}}{4}
$